14x^2-35x/2x-5

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Solution for 14x^2-35x/2x-5 equation: 


x in (-oo:+oo)

14*x^2-(((35*x)/2)*x)-5 = 0

14*x^2+(-35/2)*x^2-5 = 0

-7/2*x^2 = 5 // : -7/2

x^2 = -10/7

x belongs to the empty set

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